Haye says Wladimir wouldn’t be heavyweight champion if he were smaller

By Boxing News - 04/08/2011 - Comments

By William Mackay: WBA heavyweight champion David Haye (25-1, 23 KO’s) has for a long time felt that he had would it takes to beat IBF/WBO heavyweight champion Wladimir Klitschko (55-3, 49 KO’s). Haye doesn’t see a lot from Wladimir’s game that he admires and recently said that he wouldn’t be heavyweight champion if he were smaller.

In an article at Sky Sports, Haye said “You can tell by the way he boxes that he’s not a natural fighter. I’m sure if he was 6’3″ and weighed 210 pounds, he wouldn’t be heavyweight champion.” In other words, if Wladimir was roughly the same size as Haye, he wouldn’t be the IBF/WBO heavyweight champion. That’s kind of an odd thing for Haye to say, because it takes away the reality of what Wladimir is and puts a make belief scenario. You can twist that around by saying Haye wouldn’t be the WBA paper champion if he were fat or weak or if he actually had fought a dangerous heavyweight rather than Nikolay Valuev, who wasn’t the same fighter he once was by the time Haye fought him. Even then, Haye barely beat Valuev.

The fact of the matter is Wladimir is 6’6″ and he isn’t 6’2″ like Haye. That’s just the reality of it. I guess Haye doesn’t like the fact that Wladimir is tall and can dominate without getting hit. But I believe Wladimir would be the heavyweight champion even if he were 6’3″ 210. I mean look at how weak the heavyweight division is. All Wladimir would have to do is beat the likes of Samuel Peter, Alexander Povetkin, Kali Meehan and Ruslan Chagaev, and I believe he would be more than good enough to beat those guys at three inches shorter. Unless Haye, in his make believe scenario, would have not only smaller but weather, then I don’t see Wladimir not being the champion.



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