Adrien Broner to fight Vicente Martin Rodriguez on November 26th on Alvarez-Cintron undercard

Broner Rodriguez Broner vs. Rodriguez Alvarez vs. Cintron  saul alvarez kermit cintron adrien broner By William Mackay: Having no luck in getting Ricky Burns, the former WBO super featherweight champion, to fight him on November 26th, undefeated American Adrien Broner (21-0, 17 KO’s) will now be fighting number #6 ranked WBO contender Vicente Martin Rodriguez (34-2-1, 19 KO’s) on 10/26 on the undercard of the Kermit Cintron vs. WBC junior middleweight champion Saul Alvarez fight card on HBO as part of a triple header.

Broner-Rodriguez will take place in Broner’s home city of Cincinnati, Ohio, whereas the Alvarez-Cintron fight will take place from either Cancun or Mexico City.

The Broner vs. Rodriguez fight will be for the vacant WBO super featherweight title. They were hoping to get unbeaten Eloy Perez to take the fight but he reportedly wanted more money.

Rodriguez, 26, comes from Buenos Aires, Argentina, and has mostly 2nd tier opposition during his six year pro career. He stepped it up a level in 2008 and was soundly beaten by Australian William Kickett by a lopsided 10 round unanimous decision loss.

Rodriguez doesn’t have much in the way of hand speed, and is equally slow of foot. He’s a considerable step down from recent Broner victims Jason Litzau and Daniel Ponce De Leon. On paper, Broner vs. Rodriguez is a huge mismatch and it’s likely going to be that way in reality as well.

It’s unclear why the WBO has Rodriguez ranked so highly when he’s never fought and beat a 1st tier opponent before but he’ll likely have his ranking corrected after he loses to Broner on November 26th. This will likely be over very quickly unless Rodriguez hangs around for the full 12 just soaking up punishment.

In reviewing Rodriguez’s last fight against Mario Martinez last July, Rodriguez stalked Martinez around the ring looking to throw his slow shots. He ended up winning an unimpressive eight round decision against the 16-7 Martinez.


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